If it's not what You are looking for type in the equation solver your own equation and let us solve it.
(P)=P^2-64
We move all terms to the left:
(P)-(P^2-64)=0
We get rid of parentheses
-P^2+P+64=0
We add all the numbers together, and all the variables
-1P^2+P+64=0
a = -1; b = 1; c = +64;
Δ = b2-4ac
Δ = 12-4·(-1)·64
Δ = 257
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$P_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$P_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$P_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{257}}{2*-1}=\frac{-1-\sqrt{257}}{-2} $$P_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{257}}{2*-1}=\frac{-1+\sqrt{257}}{-2} $
| 2(x-5)^2=32 | | -39=4(y-6)-7y | | 3/4h=45/52 | | 2x-12=4+3x | | 2/3x-1/4=2/3 | | 1/4x+1/7=33 | | 1x+-4=9 | | 4a+9+2a-5=-2 | | 5(3x-(2+4x))=9-4x | | 1/3(2x-3/7)=0 | | 25-10j=-45 | | 1/3(2x-3/7)+1/6x=4/7 | | 7v+18=46 | | 3j^2–17j+14=0 | | 7+2s=15 | | v/2+7=11 | | -14+4y=6 | | 3(5x-2)+2(5x-2)=5x+10 | | 3j2–17j+14=0 | | (3x+1)=5x+66 | | 8+-3s=20 | | 4=1-4x=3 | | 3s-5=8 | | -5/3a+3=23 | | -1a=-5 | | 4x-5=(x+1) | | t-32/7=6 | | r/8+39=37 | | 0.01(x+12)-0.12=0.01(5x+12$ | | 30+10x4=160 | | n/4+-10=-6 | | 4+20=-3x+8x-11+5 |